#include <iostream>
using namespace std;
int main() {
  int n,y;
  int a=1;
  for(cin>>n;n>0;n--&&a++){
    cin>>y;
    if((y%4==0&&y%100!=0)||y%400==0)
      cout<<"Case "<<a<<": a leap year\n";
    else
      cout<<"Case "<<a<<": a normal year\n";
  }
}

限制Y的數量，將閏年的條件帶入